What is the output for the below piece of Code? #4

Question:

public class Test {

     

      public static void main(String[] args) {

            float a = 10;

            System.out.println(a/0);

      }

}

Output: 

 Infinity

Explanation:

For double and float, Arithmetic Exception is NOT thrown!
If "a" was an Integer (either byte, short, int or long), it would have thrown :

Exception in thread "main" java.lang.ArithmeticException: / by zero

      at Test.main(Test.java:9)

 

Similar Question:

public class Test {

     

      public static void main(String[] args) {

            float a = 10;

            float x = a/0;

            System.out.println(a/0+" = "+x);

      }

}

  Output:

Infinity = Infinity

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Generate Given Output #1

Question:

 
public class Test {

     

      public static void main(String[] args) {

            System.out.println("Ram");

      }

}

Modify the above code to get below output:

Hi

Ram

Bye

You shouldn’t modify main method.

Solution:

public class Test {

           

      static

      {

            System.out.println("Hi");

            main(null);

            System.out.println("Bye");

            System.exit(0);

      }

     

      public static void main(String[] args) {

            System.out.println("Ram");

      }

}

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